用java 求sn a aa aaa ……=a+aa+aaa+……+aa……a之值,其中a是一个数字。

a*(10^n-10)/81-a*n/9这个答案出错了。应该是
a*10*(10^n-1)/81-a*n/9 或者a*(10^(n+1)-10)/81-a*n/9
如果这样算的话,是计算机计算这个问题还是你计算这个问题啊。。。
您的举报已经提交成功,我们将尽快处理,谢谢!
#indlude &stdio.h&
void main()
int i,N,a=2;
long S=0,Sn=0;
scanf("%d",&N)...
double S = 0;
for(int i = 1;i &= i++)
double sum = 0;
for(int j =...
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(window.slotbydup=window.slotbydup || []).push({
id: '2081942',
container: s,
size: '1000,60',
display: 'inlay-fix'AAA+AA=976 一个A等于什么数字AAA+AA=976 一个A等于1、2、3、4、5、6、7、8、9那个数字_百度作业帮
AAA+AA=976 一个A等于什么数字AAA+AA=976 一个A等于1、2、3、4、5、6、7、8、9那个数字
A是数字8AAA即为100A+10A+AAA即为10A+A等式可以代换成 100A+10A+A+10A+A=976 然后就解出来了
其他类似问题
8 啊 这样考虑——各位是6 则A一定是3或者8 只能是8了
这个其实很简单,AAA=1000×A+100×A+10×A,我想后面的你自己应该会做了吧!呵呵、、、
A(111+11)=976
AAA+AA=100*A+10*A+A+10*A+A=122A=976A=976/122=8
扫描下载二维码Java - Methods
Java - Methods
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A Java method is a collection of statements that are grouped together to perform an operation. When you call the System.out.println() method, for example, the system actually executes several statements in order to display a message on the console.
Now you will learn how to create your own methods with or without return values, invoke a method with or without parameters, and apply method abstraction in the program design.
Creating Method:
Considering the following example to explain the syntax of a method:
public static int methodName(int a, int b) {
public static : modifier.
int: return type
methodName: name of the method
a, b: formal parameters
int a, int b: list of parameters
Method definition consists of a method header and a method body. The same is shown below:
modifier returnType nameOfMethod (Parameter List) {
// method body
The syntax shown above includes:
modifier: It defines the access type of the method and it is optional to use.
returnType: Method may return a value.
nameOfMethod: This is the method name. The method signature consists of the method name and the parameter list.
Parameter List: The list of parameters, it is the type, order, and number of parameters of a method. These are optional, method may contain zero parameters.
method body: The method body defines what the method does with statements.
Here is the source code of the above defined
method called max(). This method takes two parameters num1 and num2 and returns the maximum between the two:
/** the snippet returns the minimum between two numbers */
public static int minFunction(int n1, int n2) {
if (n1 & n2)
Method Calling:
For using a method, it should be called. There are two ways in which a method is called i.e. method returns a value or returning nothing (no return value).
The process of method calling is simple. When a program invokes a method, the program control gets transferred to the called method. This called method then returns control to the caller in two conditions, when:
return statement is executed.
reaches the method ending closing brace.
The methods returning void is considered as call to a statement. Lets consider an example:
System.out.println("This !");
The method returning value can be understood by the following example:
int result = sum(6, 9);
Following is the example to demonstrate how to define a method and how to call it:
public class ExampleMinNumber{
public static void main(String[] args) {
int a = 11;
int b = 6;
int c = minFunction(a, b);
System.out.println("Minimum Value = " + c);
/** returns the minimum of two numbers */
public static int minFunction(int n1, int n2) {
if (n1 & n2)
This would produce the following result:
inimum value = 6
The void Keyword:
The void keyword allows us to create methods which do not return a value. Here, in the following example we're considering a void method methodRankPoints. This method is a void method which does not return any value. Call to a void method must be a statement i.e. methodRankPoints(255.7);. It is a Java statement which ends with a semicolon as shown below.
public class ExampleVoid {
public static void main(String[] args) {
methodRankPoints(255.7);
public static void methodRankPoints(double points) {
if (points &= 202.5) {
System.out.println("Rank:A1");
else if (points &= 122.4) {
System.out.println("Rank:A2");
System.out.println("Rank:A3");
This would produce the following result:
Passing Parameters by Value:
While working under calling process, arguments is to be passed. These should be in the same order as their respective parameters in the method specification. Parameters can be passed by value or by reference.
Passing Parameters by Value means calling a method with a parameter. Through this the argument value is passed to the parameter.
The following program shows an example of passing parameter by value. The values of the arguments remains the same even after the method invocation.
public class swappingExample {
public static void main(String[] args) {
int a = 30;
int b = 45;
System.out.println("Before swapping, a = " +
a + " and b = " + b);
// Invoke the swap method
swapFunction(a, b);
System.out.println("\n**Now, Before and After swapping values will be same here**:");
System.out.println("After swapping, a = " +
a + " and b is " + b);
public static void swapFunction(int a, int b) {
System.out.println("Before swapping(Inside), a = " + a
+ " b = " + b);
// Swap n1 with n2
System.out.println("After swapping(Inside), a = " + a
+ " b = " + b);
This would produce the following result:
Before swapping, a = 30 and b = 45
Before swapping(Inside), a = 30 b = 45
After swapping(Inside), a = 45 b = 30
**Now, Before and After swapping values will be same here**:
After swapping, a = 30 and b is 45
Method Overloading:
When a class has two or more methods by same name but different parameters, it is known as method overloading. It is different from overriding. In overriding a method has same method name, type, number of parameters etc.
Lets consider the example shown before for finding minimum numbers of integer type. If, lets say we want to find minimum number of double type. Then the concept of Overloading will be introduced to create two or more methods with the same name but different parameters.
The below example explains the same:
public class ExampleOverloading{
public static void main(String[] args) {
int a = 11;
int b = 6;
double c = 7.3;
double d = 9.4;
int result1 = minFunction(a, b);
// same function name with different parameters
double result2 = minFunction(c, d);
System.out.println("Minimum Value = " + result1);
System.out.println("Minimum Value = " + result2);
// for integer
public static int minFunction(int n1, int n2) {
if (n1 & n2)
// for double
public static double minFunction(double n1, double n2) {
if (n1 & n2)
This would produce the following result:
inimum Value = 6
inimum Value = 7.3
Overloading methods makes program readable. Here, two methods are given same name but with different parameters. The minimum number from integer and double types is the result.
Using Command-Line Arguments:
Sometimes you will want to pass information into a program when you run it. This is accomplished by passing command-line arguments to main( ).
A command-line argument is the information that directly follows the program's name on the command line when it is executed. To access the command-line arguments inside a Java program is quite easy.they are stored as strings in the String array passed to main( ).
The following program displays all of the command-line arguments that it is called with:
public class CommandLine {
public static void main(String args[]){
for(int i=0; i&args. i++){
System.out.println("args[" + i + "]: " +
Try executing this program as shown here:
$java CommandLine this is a command line 200 -100
This would produce the following result:
args[0]: this
args[1]: is
args[2]: a
args[3]: command
args[4]: line
args[5]: 200
args[6]: -100
The Constructors:
A constructor initializes an object when it is created. It has the same name as its class and is syntactically similar to a method. However, constructors have no explicit return type.
Typically, you will use a constructor to give initial values to the instance variables defined by the class, or to perform any other startup procedures required to create a fully formed object.
All classes have constructors, whether you define one or not, because Java automatically provides a default constructor that initializes all member variables to zero. However, once you define your own constructor, the default constructor is no longer used.
Here is a simple example that uses a constructor without parameters:
// A simple constructor.
class MyClass {
// Following is the constructor
MyClass() {
You would call constructor to initialize objects as follows:
public class ConsDemo {
public static void main(String args[]) {
MyClass t1 = new MyClass();
MyClass t2 = new MyClass();
System.out.println(t1.x + " " + t2.x);
parametarized constructor
Most often, you will need a constructor that accepts one or more parameters. Parameters are added to a constructor in the same way that they are added to a method, just declare them inside the parentheses after the constructor's name.
Here is a simple example that uses a constructor with parameter:
// A simple constructor.
class MyClass {
// Following is the constructor
MyClass(int i ) {
You would call constructor to initialize objects as follows:
public class ConsDemo {
public static void main(String args[]) {
MyClass t1 = new MyClass( 10 );
MyClass t2 = new MyClass( 20 );
System.out.println(t1.x + " " + t2.x);
This would produce the following result:
The this keyword
this is a keyword in Java which is used as a reference to the object of the current class, with in an instance method or a constructor. Using this you can refer the members of a class such as constructors, variables and methods.
NoteThe keyword this is used only within instance methods or constructors
In general the keyword this is used to :
Differentiate the instance variables from local variables if they have same names, within a constructor or a method.
class Student{
Student(int age){
one type of constructor( parametrized constructor or default ) from other in a class. It is known as explicit constructor invocation .
class Student{
Student(){
Student(int age){
Here is an example that uses this keyword to access the members of a class. Copy and paste the below given program in a file with name This_Example.java
public class This_Example {
//Instance variable num
int num=10;
This_Example(){
System.out.println("This is an example program on keyword this ");
This_Example(int num){
//Invoking the default constructor
//Assigning the local variable num to the instance variable num
public void greet(){
System.out.println("Hi Welcome to Tutorialspoint");
public void print(){
//Local variable num
int num=20;
//Printing the instance variable
System.out.println("value of local variable num is : "+num);
//Printing the local variable
System.out.println("value of instance variable num is : "+this.num);
//Invoking the greet method of a class
this.greet();
public static void main(String[] args){
//Instantiating the class
This_Example obj1=new This_Example();
//Invoking the print method
obj1.print();
//Passing a new value to the num variable through parametrized constructor
This_Example obj2=new This_Example(30);
//Invoking the print method again
obj2.print();
This would produce the following result:
This is an example program on keyword this
value of local variable num is : 20
value of instance variable num is : 10
Hi Welcome to Tutorialspoint
This is an example program on keyword this
value of local variable num is : 20
value of instance variable num is : 30
Hi Welcome to Tutorialspoint
Variable Arguments(var-args):
JDK 1.5 enables you to pass a variable number of arguments of the same type to a method. The parameter in the method is declared as follows:
typeName... parameterName
In the method declaration, you specify the type followed by an ellipsis (...) Only one variable-length parameter may be specified in a method, and this parameter must be the last parameter. Any regular parameters must precede it.
public class VarargsDemo {
public static void main(String args[]) {
// Call method with variable args
printMax(34, 3, 3, 2, 56.5);
printMax(new double[]{1, 2, 3});
public static void printMax( double... numbers) {
if (numbers.length == 0) {
System.out.println("No argument passed");
double result = numbers[0];
for (int i = 1; i &
numbers. i++)
if (numbers[i] &
result = numbers[i];
System.out.println("The max value is " + result);
This would produce the following result:
The max value is 56.5
The max value is 3.0
The finalize( ) Method:
It is possible to define a method that will be called just before an object's final destruction by the garbage collector. This method is called finalize( ), and it can be used to ensure that an object terminates cleanly.
For example, you might use finalize( ) to make sure that an open file owned by that object is closed.
To add a finalizer to a class, you simply define the finalize( ) method. The Java runtime calls that method whenever it is about to recycle an object of that class.
Inside the finalize( ) method, you will specify those actions that must be performed before an object is destroyed.
The finalize( ) method has this general form:
protected void finalize( )
// finalization code here
Here, the keyword protected is a specifier that prevents access to finalize( ) by code defined outside its class.
This means that you cannot know when or even if finalize( ) will be executed. For example, if your program ends before garbage collection occurs, finalize( ) will not execute.
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